Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
উপহাৰ | 108 | 13 | 1 | 13.0000 |
ৰূপান্তৰ | 69 | 10 | 1 | 10.0000 |
বসন্ত | 85 | 10 | 1 | 10.0000 |
দৰা | 58 | 9 | 1 | 9.0000 |
মুৰব্বী | 89 | 8 | 1 | 8.0000 |
জমা | 115 | 8 | 1 | 8.0000 |
অৱশ্যে | 662 | 24 | 3 | 8.0000 |
ছপা | 116 | 8 | 1 | 8.0000 |
স্বৰ্গদেউ | 72 | 8 | 1 | 8.0000 |
ভয় | 95 | 8 | 1 | 8.0000 |
২৫ | 185 | 22 | 3 | 7.3333 |
আঁতৰি | 106 | 14 | 2 | 7.0000 |
খান | 89 | 7 | 1 | 7.0000 |
উজনি | 109 | 7 | 1 | 7.0000 |
পোহৰৰ | 81 | 7 | 1 | 7.0000 |
২১ | 147 | 14 | 2 | 7.0000 |
দুৰ্বল | 111 | 7 | 1 | 7.0000 |
আগুৱাই | 61 | 7 | 1 | 7.0000 |
২৭ | 104 | 14 | 2 | 7.0000 |
কল্পনা | 71 | 7 | 1 | 7.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
কৰিছে। | 1696 | 1 | 103 | 0.0097 |
নাই। | 658 | 1 | 38 | 0.0263 |
জুনত | 70 | 1 | 11 | 0.0909 |
জুলাইত | 69 | 1 | 10 | 0.1000 |
হ'ব। | 157 | 1 | 9 | 0.1111 |
ছেপ্টেম্বৰত | 71 | 1 | 8 | 0.1250 |
যুগত | 90 | 1 | 8 | 0.1250 |
ভাতৃ | 91 | 1 | 8 | 0.1250 |
একাধিক | 171 | 1 | 8 | 0.1250 |
The | 155 | 1 | 8 | 0.1250 |
আগলৈকে | 70 | 1 | 8 | 0.1250 |
পৰিমাণৰ | 137 | 2 | 15 | 0.1333 |
আগতেই | 116 | 1 | 7 | 0.1429 |
বৰ্ষত | 79 | 1 | 7 | 0.1429 |
পাৰৰ | 73 | 1 | 7 | 0.1429 |
ফালৰ | 152 | 2 | 13 | 0.1538 |
সেইবোৰ | 113 | 1 | 6 | 0.1667 |
শেষত | 305 | 2 | 12 | 0.1667 |
আগে | 138 | 1 | 6 | 0.1667 |
সময়তেই | 43 | 1 | 6 | 0.1667 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II